The squirrel hand-cut rasp

November 2011

Some time ago, I got in touch with a friendly group of luthiers. Since then, I try to develop a new rasp which is more particularly suited to some violin makers work, and inspired by the famous tiny planes they use :

The idea is inspired by the shape of these tiny planes – for its maneuverability and the accessibility – using a wooden handle. The wood handle receives below a « sole » of steel with the same radii as the tiny planes, and designed to be stitched with quite fine teeth (probably a stitching grain #14). If you click on the picture below to enlarge it you will see the different shape of handles that have been suggested to me so far. For now my preference goes to model in the lower left corner  (thank you Caribou).

All opinions, comments, encouragement, criticism, etc.. are welcome, even on the name to be given to this new rasp.

6 réponses à The squirrel hand-cut rasp

  1. Strongly suggest adding a « google+ » button for the blog!

  2. admin_liogier dit :

    Yes, thanks. We just added one in the right column of the page, below « contact ».

  3. Nice idea Noel. I do archtop guitars as well and though normally I am using japanese spoon bottom planes for this I am extremely interested in this project. What is the approximate size? It looks like the various possible shapes vary some in size.

    Also what is the possibility of getting a couple different Radii?


    • admin_liogier dit :

      The first « squirrel rasp » will be 38 mm long and 22 mm wide (the steel part, without the handle), with the same radius of the equivalent Ibex plane. Then we plan to develop other models with different radii.

  4. FenceFurniture dit :

    If you want to work out the radius of any half-round (rasp, file or whatever) you need the height of the profile(h) and the width(w). The formula is then:

    radius = h/2 + w*w/8/h

    It’s a little bit trickier when it comes to Sage Leaf (Crossing) profiles with their two half-rounds. Still the same formula, but you need to split the height between the two radii. I guess the split is around 1/3 and 2/3 and perhaps Noel can shed some light there.